Página — Matematica 8° Secundaria (pág. 102)

Repetimos de nuevo, todo el proceso anterior:

\frac{x^{3}+5x^{2}+x+10}{x^{3}+2x^{2}+x}=\frac{x-2}{x^{2}+7x}

Repetimos el proceso, bajando (+10)y formando el polinomio 15x+10

\frac{x^{3}+5x^{2}+x+10}{x^{3}+2x^{2}+x}=\frac{x-2}{x^{2}+7x+15}=\frac{x-2}{x^{2}+7x+15}=\frac{x-2}{x^{2}+7x+15}=\frac{x-2}{x^{2}+7x+15}=\frac{x-2}{x^{2}+7x+15}=\frac{x-2}{x^{2}+7x+15}=\frac{x-2}{x^{2}+7x+15}=\frac{x-2}{x^{2}+7x+15}=\frac{x-2}{x^{2}+7x+15}=\frac{x-2}{x^{2}+7x+15}=\frac{x-2}{x^{2}+7x+15}=\frac{x-2}{x^{2}+7x+15}=\frac{x-2}{x^{2}+7x+15}=\frac{x-2}{x^{2}+7x+15}=\frac{x-2}{x^{2}+7x+15}=\frac{x-2}{x^{2}+7x+15}=\frac{x-2}{x^{2}+7x+15}=\frac{x-2}{x^{2}+7x+15}=\frac{x-2}{x^{2}+7x+15}=\frac{x-2}{x^{2}+7x+15}=\frac{x-2}{x^{2}+7x+15}=\frac{x-2}{x^{2}+7x+15}=\frac{x-2}{x^{2}+7x+15}=\frac{x-2}{x^{2}+7x+15}=\frac{x-2}{x^{2}+7x+15}=\frac{x-2}{x^{2}+7x+15}=\frac{x-2}{x^{2}+7x+15}=\frac{x-2}{x^{2}+7x+15}=\frac{x-2}{x^{2}+7x+15}=\frac{x-2}{x^{2}+7}=\frac{x^{2}+7}=\frac{x^{2}+7}{x^{2}+7}=\frac{x^{2}+7}=\frac{x^{2}+7}=\frac{x^{2}+7}{x^{2}+7}=\frac{x^{2}+7}=\frac{x^{2}+7}=\frac{x^{2}+7}=\frac{x^{2}+7}=\frac{x^{2}+7}=\frac{x^{2}+7}=\frac{x^{2}+7}=\frac{x^{2}+7}=\frac{x^{2}+7}=\frac{x^{2}+7}=\frac{x^{2}+7}=\frac{x^{2}+7}=\frac{x^{2}+7}=\frac{x^{2}+7}=\frac{x^{2}+7}=\frac{x^{2}+7}=\frac{x^{2}+7}=\frac{2}=\frac{x^{2}}=\frac{x^{2}}=\frac{x^{2}}=\frac{x^{2}+7}=\frac{2}=\frac{x^{2}}=\frac{2}=\frac{x^{2}}=\frac{2}=\frac{2}=\frac{x^{2}=x^{2}}=\frac{2}=\frac{2}=\frac{2}=\frac{2}{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{\frac{2}=\frac{2}=\frac{2}=\frac{2}{2}=\frac{\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{\frac{2}=\frac{2}=\frac{\frac{2}=\frac{2}=\frac{2}=\frac{2}=\frac{\frac{2}=\frac{\frac{2}=\frac{2}=\frac{\frac{2}}=\frac{\frac{2}=\frac{\frac{2}}=\frac{\frac{2}=\frac{\frac{\frac{2}}=\frac{\frac{2}}}=\frac{\frac{\frac{\frac{2}}}=\frac{\frac{\frac{\frac{\frac{\frac{2}}}}}=\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{2}}}}}}}=\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{}}}}}}}}}}}}=\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{}}}}}}}}}}}}}}}=\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{}}}}}}}}}}}}}}}}}}{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{}}}}}}}}}}}}}}}}}}}{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{}}}}}}}}}}}}}}}}}}{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{}}}}}}}}}}}}}}}}}}{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{}}}}}}}}}}}}}}}}}\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{}}}}}}}}}}}}}}{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{}}}}}}}}}}}}}}\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{}}}}}}}}}}}}}}}}\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\

• iCuál es cociente de la división?

•iCuál es el residuo?

Formen grupos de tres estudiantes.

1. Busquen el factor, que multiplicado en cada caso por el monomio dado, dé como resultado 15x²y.

a.5x

b.1

C.\frac{15}{4}x

d. xy

Guia g·Postprimaria Rural