Página — Matematica 9° Secundaria (pág. 213)

Unidad 4

2.2,900 aproximadamente, son menores de 15 años 3.

a)\mathrm{Media}=5.9 b)\mathrm{Media}=6 c)M o d a=3y8

\left(\frac{7}{28}\right)\cdot\left(\frac{6}{27}\right)\cdot\left(\frac{8}{26}\right)\cdot\left(\frac{4}{25}\right)=\frac{480}{4,91400}=\frac{1}{585}

\frac{4}{78}\cdot\left(\frac{3}{6}\right)\cdot\left(\frac{3}{5}\right)\cdot\left(\frac{2}{4}\right)\cdot\left(\frac{2}{3}\right)\cdot\left(\frac{1}{2}\right)\cdot\left(\frac{1}{1}\right)=\frac{144}{5,040}=\frac{1}{35}

P(\S1,000)=\frac{1}{6}\quad;\quad P(\S2,000)=\frac{1}{3}

P(\S5,000)=\frac{1}{6}\quad;\quad P(\S10,000)=\frac{1}{3}

P(B\dot{o}A)=P(B)+P(A)=\frac{4}{10}+\frac{1}{10}=\frac{1}{2}

P(R\acute{o}N)=P(B)+P(N)=\frac{3}{10}+\frac{2}{10}=\frac{1}{2}

P(B\dot{o}N)=P(B)+P(N)=\frac{4}{10}+\frac{2}{10}=\frac{1}{2}

a)

P(As)=\frac{4}{40}=\frac{1}{10}

b)

P(R\acute{o}N)=P(B)+P(N)=\frac{3}{10}+\frac{2}{10}=\frac{1}{2}

P(Cabdeesposotadecopas)=P(CabE)+P(SdeC)=\frac{1}{40}+\frac{1}{40}=\frac{1}{20}

Mes	Capital ($)	Tasa
10	500,000	4.5%	22,500	522,500
20	522,500	4.5%	23,510	546,010
30	546,010	4.5%	24,570	570,580

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