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Unidad 1· La era digital
Lección 1Numeros enteros
Multiplicación de números enteros
- Representa en la recta numérica cada multiplicación y calcula el producto.
a.
4\cdot(-4)=\boxed{\quad\quad\quad}
\begin{aligned}&\mathbf{b}.\ 5\cdot(-3)=\begin{bmatrix}\\ &-1&-1&-1&-1&-1&-1&-1&-1&-1&-1&-1&-1&-1&-1&-1&-1&-1&-1&-1&-1&-1&-1\\&\end{bmatrix}\\ \end{aligned}
C.
(-2)\cdot6=\left\{\begin{array}{l}\quad\ll\left|\begin{array}{c}\end{array}\right|+1+1+\left|\begin{array}{c}\end{array}\right|+1+\left|\begin{array}{c}\end{array}\right|+1+\left|\begin{array}{c}\end{array}\right|+1+\left|\begin{array}{c}\end{array}\right|+1+\left|\begin{array}{c}\end{array}\right|+\left|\begin{array}{c}\end{array}\right|+\left|\begin{array}{c}\end{array}\right|+\left|\begin{array}{c}\end{array}\right|+\left|\begin{array}{c}\end{array}\right|+\left|\begin{array}{c}\end{array}\right|\gg\left\{\begin{array}{c}\end{array}\right|+\left|\begin{array}{c}\end{array}\right|+\left|\begin{array}{c}\end{array}\right|+\left|\begin{array}{c}\end{array}\right|+\left|\begin{array}{c}\end{array}\right|+\left|\begin{array}{c}\end{array}\right|+\left|\begin{array}{c}\end{array}\right|+\left|\begin{array}{c}\end{array}\right|+\left|\begin{array}{c}\end{array}\right|+\left|\begin{array}{c}\end{array}\right|+\left|\begin{array}{c}\end{array}\right|+\left|\begin{array}{c}\end{array}\right|+\left|\begin{array}{c}\end{array}\right|+\left|\begin{array}{c}\end{array}\right|+\left|\begin{array}{c}\end{array}\right|+\left|\begin{array}{c}\end{array}\right|+\left|\begin{array}{c}\end{array}\right|+\left|\begin{array}{c}\end{array}\right|+\left|\begin{array}{c}\end{array}\right|+\left|\begin{array}{c}\end{array}\right|+\left|\begin{array}{array}\right|+\left|\begin{array}{c}\end{array}\right|+\left|\begin{array}{array}\end{array}\right|+\left|\begin{array}{array}\end{array}\right|+\left|\begin{array}{array}\end{array}\right|+\left|\begin{array}{array}\end{array}\right|+\left|\begin{array}{array}\end{array}\right|+\left|\begin{array}\end{array}\right|+\left|\begin{array}\end{array}\right|+\left|\begin{array}\end{array}\right|+\left|\begin{array}\end{array}\right|+\left|\begin{array}\end{array}\right|+\left|\begin{array}\end{array}\right|+\left|\begin{array}\begin{array}\end{array}\right|+\left|\begin{array}\end{array}\right|+\left|\begin{array}\end{array}\right|+\left|\begin{array}\begin{array}\end{array}\right|+\left|\begin{array}\end{array}\right|+\left|\begin{array}\end{array}\right|+\left|\begin{array}\end{array}\right|+\left|\begin{array}\end{array}\right|+\left\left|\begin{array}\begin{array}\end{array}\right|+\left\right|\end{array}\right|+\left\left\|\begin{array}\begin{array}\end{array}\right|+\left\right|\end{array}\right|+\left\left\|\begin{array}\end{array}\right|+\left\left\begin{array}\end{array}\right|\end{array}\right|+\left\left\begin{array}\end{array}\right|\end{array}\right|+\left\left\begin{array}\end{array}\right|\end{array}\right|+\left\left\begin{array}\begin{array}\end{array}\begin{array}\end{array}\end{array}\begin{array}\end{array}\end{array}\begin{array}\begin{array}\begin{array}\end{array}\begin{array}\end{array}\begin{array}\begin{array}\begin{array}\begin{array}\end{array}\begin{array}\begin{array}\begin{array}\end{array}\begin{array}\begin{array}\begin{array}\begin{array}\end{array}\begin{array}\begin{array}\end{array}\begin{array}\end{array}\begin{array}\begin{array}\begin{array}\end{array}\begin{array}\end{array}\begin{array}\end{array}\begin{array}\begin{array}\begin{array}\end{array}\begin{array}\begin{array}\end{array}\begin{array}\begin{array}\end{array}\begin{array}\begin{array}\end{array}\end{array}\begin{array}\begin{array}\end{array}\begin{array}\begin{array}\begin{array}\end{array}\begin{array}\end{array}\end{array}\begin{array}\begin{array}\begin{array}\begin{array}\begin{array}\end{array}\begin{array}\begin{array}\end{array}\begin{array}\end{array}\begin{array}\begin{array}\end{array}\begin{array}\begin{array}\end{array}\end{array}\begin{array}\begin{array}\begin{array}\end{array}\begin{array}\end{array}\begin{array}\begin{array}\end{array}\end{array}\begin{array}\begin{array}\begin{array}\end{array}\begin{array}\begin{array}\end{array}\begin{array}\begin{array}\end{array}\begin{array}\end{array}\begin{array}\begin{array}\begin{array}\end{array}\begin{array}\end{array}\begin{array}\begin{array}\begin{array}\end{array}\end{array}\begin{array}\begin{array}\end{array}\begin{array}\begin{array}\begin{\end{array}\end{array}\begin{array}\begin{array}\end{array}\begin{array}\begin{array}\end{array}\begin{\end{array}\begin{\end{array}\end{array}\begin{array}\end{array}\begin{array}\end{array}\begin{array}\begin{array}\begin{\begin{array}\end{array}\end{array}\begin{array}\end{array}\begin{array}\begin{array}\begin{array}\begin{\end{array}\end{array}\begin{array}\begin{array}\begin{array}\end{\begin{array}\begin{array}\end{\end{array}\begin{array}\begin{array}\end{array}\begin{array}\begin{array}\begin{array}\end{array}\begin{array}\begin{array}\begin{array}\begin{\end{array}\begin{array}\begin{array}\end{array}\begin{array}\begin{array}\begin{array}\begin{array}\begin{array}\end{array}\begin{\end{array}\end{array}\begin{array}\begin{array}\begin{
d.
\begin{aligned}&(-8)\bullet1=\begin{vmatrix}\\ &\end{vmatrix}\\ &\quad\blacktriangleleft\begin{vmatrix}+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1\end{vmatrix}\\ &\quad-20\quad-15\quad-10\quad-5\quad0\quad5\quad10\quad15\quad20\\ \end{aligned} (-8)\cdot1=\boxed{\hspace{2cm}} \begin{aligned}&(-8)\bullet1=\begin{vmatrix}\\ &\end{vmatrix}\\ &\quad\blacktriangleleft\begin{vmatrix}+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1\end{vmatrix}\\ &\quad-20\quad-15\quad-10\quad-5\quad0\quad5\quad10\quad15\quad20\\ \end{aligned}
- Resuelve las siguientes multiplicaciones:
a.
(-5)\cdot6=\boxed{\hspace{2cm}}
(-8)\cdot4=\boxed{\quad}
g.
(-8)\cdot8=\boxed{\hspace{2cm}}
b.
(-1)\cdot(-10)=\boxed{\quad}
\mathbf{e},\quad(-3)\cdot(-9)=\boxed{\quad}
h.
(-15)\cdot0=\boxed{\quad}
C
1\cdot(-1)=\sqrt[3]{}
17\cdot(-4)=\boxed{\quad}
30\cdot(-2)=\boxed{\quad}
- Respetando la prioridad de las operaciones, calcula el resultado de cada expresión.
a.
5\cdot(-3)+(-2)\cdot9=\boxed{\hspace{2cm}}
C.
(-2)\cdot(-6)+10\cdot(-3)=\boxed{\quad}
b.
(-4)\cdot(-3)\cdot(-2)\cdot(-3)=\boxed{\begin{aligned}&\\ &\end{aligned}}
d.
(-3)\cdot(5+4)\cdot(-2)=\boxed{\quad}




6
Unidad1
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