Ejemplo 2
Para resolver las operaciones se respeta este orden: paréntesis, multiplicaciones y divisiones, sumas y restas, y finalmente potencias.
\left[\left(\frac{3}{2}-\frac{2}{3}\times\frac{12}{3}\right)-\left(\frac{10}{2}+\frac{3}{5}\right)\div\left(\frac{3}{4}+\frac{1}{3}\right)\right]\div\left(\frac{3}{6}-\frac{4}{3}\right)
Primero resolvemos los paréntesis:
\frac{2}{3}\times\frac{12}{3}=\frac{8}{3},\qquad \frac{3}{2}-\frac{8}{3}=-\frac{7}{6}
\frac{10}{2}+\frac{3}{5}=\frac{28}{5},\qquad \frac{3}{4}+\frac{1}{3}=\frac{13}{12}
\frac{3}{6}-\frac{4}{3}=\frac{1}{2}-\frac{4}{3}=-\frac{5}{6}
Resolvemos la división dentro del corchete:
\frac{28}{5}\div\frac{13}{12}=\frac{28}{5}\times\frac{12}{13}=\frac{336}{65}
Luego operamos dentro del corchete:
-\frac{7}{6}-\frac{336}{65} = -\frac{455}{390}-\frac{2016}{390} = -\frac{2471}{390}
Finalmente:
-\frac{2471}{390}\div\left(-\frac{5}{6}\right) = -\frac{2471}{390}\times\left(-\frac{6}{5}\right) =\frac{2471}{325} =7\frac{196}{325}
\left[\frac{\left(\frac{3}{4}+\frac{2}{5}\times\frac{15}{4}\right)\div\left(\frac{3}{2}-\frac{4}{3}\right)}{\frac{3}{4}+\frac{5}{2}\times\left(\frac{1}{4}+\frac{5}{2}\right)}\right]^2
Resolvemos los paréntesis del numerador:
\frac{2}{5}\times\frac{15}{4}=\frac{3}{2},\qquad \frac{3}{4}+\frac{3}{2}=\frac{9}{4}
\frac{3}{2}-\frac{4}{3}=\frac{1}{6}
En el denominador:
\frac{1}{4}+\frac{5}{2}=\frac{11}{4},\qquad \frac{5}{2}\times\frac{11}{4}=\frac{55}{8}
\frac{3}{4}+\frac{55}{8}=\frac{6}{8}+\frac{55}{8}=\frac{61}{8}
Entonces:
\left[\frac{\frac{9}{4}\times\frac{1}{6}}{\frac{61}{8}}\right]^2 =\left[\frac{\frac{3}{8}}{\frac{61}{8}}\right]^2 =\left[\frac{3}{8}\times\frac{8}{61}\right]^2 =\left(\frac{3}{61}\right)^2 =\frac{9}{3721}








